Question

If a = 4q + r then what are the conditions for a and q. What are the values
that r can take?

Answer 1

Hi,

This is related to Euclid's division lemma

Let a and b be any two positive integers. Then there exist two unique

whole numbers q and r such that

a = bq + r , 0 less or equal to r less than b

Here , a is called the dividend , b is called the divisor , q is called

the quotient and r is called the remainder.

Given a = 4q + r

We apply the division algorithm, with a and b = 6.

Since 0 less or equal to r less than 4,

the possible remainders are 0, 1, 2 , 3

That is , a can be

4q or 4q +1 or 4q + 2 or 4q + 3

Where q is the quotient.

I hope this will usful to you.

*****

Answer 2

Answer:

Let "a" be any positive integer.

By Euclid's division lemma, a= bq + r 0 is less than or equal to r less than b.

here, b= 4 , a= 4q + r 0 0 is less than or equal to r less than 4 .

Possible Remainders = 0,1, 2 and 3

hence , a = 4q

a= 4q+1

a= 4q+2

a= 4q+3

I hope it is useful for you.

please make me brainliest.

Thanks