Question

if A=4x²+y²–6xy B=3y²+12x²+8xy then find A–3B ​

Answer 1

$a - 3b \\ 4 {x}^{2} + {y}^{2} - 6xy - (3 \\ \times 3 {y}^{2} + 12 {x}^{2} + 8xy) \\4 {x}^{2} + {y}^{2} - 6xy -$

solve by. yourself

Answer 2

Answer:

A-3B=−32x^2−8y^2−30xy

Step-by-step explanation:

Given that,

A=4x^2+y^2−6xy

B=3y^2+12x^2+8xy

A−3B=(4x°2+y^2−6xy)−3(3y^2+12x^2+8xy)

=(4x^2+y^2−6xy)−(36x^2+9y^2+24xy)

=−32x^2−8y^2−30xy