Math, asked by nopgsangsuvershast, 1 year ago

If a=√5+1/√5-1 and b=√5-1/√5+1, find the value of a^2+ab+b^2/a^2-ab+b^2

Answers

Answered by reddykarthik104
3
(1/(a2+ab+ac))+(1/(c2+ac+bc))+(1/(a2+ab+ac))
=(1/a(a+b+c))+(1/b(a+b+c))+(1/c(a+b+c))
By taking LCM we get
=(ab + bc + ca)/[(a+b+c)(abc)]
put, ab+bc+ca=0
you get value = 0/[(a+b+c)(abc)] = 0
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