Question

if a=5+2✓6 and b=1/a then what will be the value of a^2+b^2

Answer 1

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Answer 2

Solution:

a=5+2√6

b=$\frac{1}{a}$ = $\frac{1}{5+2√6}$x$\frac{5-2√6}{5-2√6}$

⇒$\frac{5-2√6}{(5)^{2}-(2√6)^{2} }$

⇒$\frac{5-2√6}{25-24}$

⇒5-2√6

So a²+b²

     ⇒ (5+2√6)² + (5-2√6)²

     ⇒ 25+24+20√6 + 25+24-20√6

     ⇒ 49+49

     ⇒ 98