If a(5,2), b(2,-2) and c(-2,t) are the vertices ofa right triangle with angle b=90°.Then find the value of t.
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by pythogoras theorem,
ac^2=ab^2+bc^2
(5+2)^2+(2-t)^2=(5-2)^2+(2+2)^2+(2+2)^2+(-2-t)^2
49+(2-t)^2=9+16+16+(2+t)^2
49+4+t^2-4t=41+4+t^2+4t
8-4t=4t
t=1
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