if A(5,2),B(2,-2) and the ventures of a right angle triangle with angle B=90 then find the value of 1
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Answered by
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Using Pythagoras theorem in right triangle ABC, we obtain
AC 2
=AB 2 +BC 2
⇒(5+2)
2 +(2−t)
2
={(5−2) 2 +(2+2) 2 }+{(2+2) 2 +(−2−t) 2 }
⇒49+(4−4t+t^2 )=(9+16)+(16+4+4t+t 2 )
⇒t 2
−4t+53
=t 2
+4t×45
⇒−8t=−8
⇒t=1
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