Question

If (a-5)²+(b-c)²+(c-d)²+(b+c+d-9)²=0 then the value of (a+b+c)(b+c+d) is.....

Answer 1

Answer :-

→ 99 .

Step-by-step explanation :-

°•° (a – 5)² + (b – c)² + (c – d)² + (b + c + d – 9)² = 0.

Therefore,

==> a – 5 = 0 or a = 5 ... (i).

==> b – c = 0 or b = c...(ii) .

==> c – d = 0 or c = d ...(iii) .

==> b + c + d – 9 = 0 ... (iv) .

Now,

•°• b = c = d ...(v). [ From equation (ii) and (iii) . ]

So, by equation (ii) and (iii), we get

==> 3b = 9.

•°• b = 3.

So,

•°• a = 5, b = 3, c = 3 and d = 3 .

Now,

= ( a + b + c )( b + c + d ) .

= (5 + 3 + 3) (3 + 3 + 3) .

= (11) (9) .

= 99 .

Hence, it is solved.

Answer 2

Hello mate this is very tough and interesting question

but tension not I am here only for you

Your answer is in the upper Image so see it and solve your doubt