Question

If a= 5+2 underroot6 then find the value of a square+ 1/A square​

Answer 1

Answer:

Answer ♡

Here,

a = 5 + 2√6 b = 1/a =1 /( 5 + 2√6)

=(5 -2√6)/(5+2√6)(5 -2√6)

=(5 - 2√6)/{5² -(2√6)²}

=(5 -2√6)/(25 -24) =5 -2√ 6

Now,

a² + b² = (a + b)² -2ab

=(5 +2 √6)^2-2(5+2√6)(5-2√6)

=(10)^2-2(25-24)

=100-2

=98

Hence,The answer is 98.

Answer 2

Answer:

${\huge{\pink{↬}}} \:  \: {\huge{\underline{\boxed{\bf{\pink{Answer}}}}}}$

Here,

a = 5 + 2√6 b = 1/a =1/(5 + 2√6)

=(5-2√6)/(5+2√6)(5 -2-√6)

=(5-2√6)/{5² -(2-√6)²} =(5-2-√6)/(25-24)=5 -2√ 6

Now,

a² + b² = (a + b)² -2ab

=(5 +2 √6)^2-2(5+2√6)(5-2√6)

=(10)^2-2(25-24)

=100-2

=98

Hence,The answer is 98.