If a= 5+2 underroot6 then find the value of a square+ 1/A square
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Answered by
4
Answer:
Answer ♡
Here,
a = 5 + 2√6 b = 1/a =1 /( 5 + 2√6)
=(5 -2√6)/(5+2√6)(5 -2√6)
=(5 - 2√6)/{5² -(2√6)²}
=(5 -2√6)/(25 -24) =5 -2√ 6
Now,
a² + b² = (a + b)² -2ab
=(5 +2 √6)^2-2(5+2√6)(5-2√6)
=(10)^2-2(25-24)
=100-2
=98
Hence,The answer is 98.
Answered by
20
""" ❤️ Answer ❤️ """
A
=
5+2
6
=
3+2+2
3×2
=
(
3
) 2
2
) 2
3
2
=
(
3
+
2
) 2
=
3
+
2
∴
A
+
A
1
=
(
3
+
2
)+
(
3
+
2
)
1
=(
3
+
2
)+
(
3
+
2
)(
3
−
2
)
3
−
2
=
(
3
+
2
)+
3−2
3
−
2
=
3
+
2
+
3
−
2
= 2
3
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