If a = (√5-√3)/(√5+√3) and b = (√5+√3)/(√5-√3), then find the value of a^2 +b^2-6ab
Answers
Answered by
4
We know (x+y)(x-y) = x^2 - y^2
a = (√5-√3)/(√5+√3)
Multiplying (√5-√3) to numerator and denominator
8-2√15/2
= 4 - √15
b = 1/a = 4+ √15
a^2 +b^2-6ab
= (a-b)^2 - 4ab
(-2√15)^2 - 4[ 4^2 - (√15)^2]
=60 - 4 =56
a = (√5-√3)/(√5+√3)
Multiplying (√5-√3) to numerator and denominator
8-2√15/2
= 4 - √15
b = 1/a = 4+ √15
a^2 +b^2-6ab
= (a-b)^2 - 4ab
(-2√15)^2 - 4[ 4^2 - (√15)^2]
=60 - 4 =56
Similar questions