if a = √5+3/√5-3 and b = √5-3/√5+3, then find the value of a²+b²+ab
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Hey there
So let's solve your your problem step by step.
We know that
(a+b)^2=a^2 + b^2 + 2ab.
So
We already have values for LHS as 5 and value of ab as 3.
So,
(a+b)^2 =5^2 = 25
And, 2ab = 2*3 = 6
Now we substitute the values for both in general equation and we get,
25 = a^2 + b^2 + 6
a^2 + b^2 = 25 -6 = 19.
Therefore, the answer to your question is 19.
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