Math, asked by rockingrohit3016, 8 months ago

If A = {5,6}, B = {4,5,6} , C = {5,6,7} ,Show that AxA = (BxB) n (CxC).

Answers

Answered by Anonymous
36

A × A = {(5,5),(5,6),(6,5),(6,6)}

B × B = {(4,4),(4,5),(4,6),(5,4),(5,5),(5,6),(6,4),(6,5),(6,6)}

C × C = {(5,5),(5,6),(5,7),(6,5)(6,6),(6,7),(7,5)(7,6),(7,7)}

Now ,

➡A × A = (BxB) n (CxC)

➡ {(5,5),(5,6),(6,5),(6,6)} = {(4,4),(4,5),(4,6),(5,4),(5,5),(5,6),(6,4),(6,5),(6,6)} n {(5,5),(5,6),(5,7),(6,5)(6,6),(6,7),(7,5)(7,6),(7,7)}

➡ {(5,5),(5,6),(6,5),(6,6)} = {(5,5),(5,6),(6,5),(6,6)}

Hence proved

Sahana?? :"(

Answered by sakthisundaresan33
1

Step-by-step explanation:

10.If A={5,6},B={4,5,6} C={5,6,7} show that AxA=(BxB)

(CxC)

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