If A (-5,7)B (-4,-5) c(-1,-6)andD(4,5)are the vertices of a quadrilateral Then,find the area of the quadrilateral ABCD.
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Ans:
By joining B to D ,you will get two triangles ABD,BCD.
The area of triangle ABD
=1/2[-5(-5-5)+(-4)(5-7)+4(7+5)
=1/2(50+8+48)=106/2=53 square units....
Also,
The area of triangle BCD =1/2[-4(-6-5)-1(5+5)+4(-5+6)
=1/2[44-10+4]=19 square units...
Area of Triangle ABD + area of triangle BCD
so,
the are of quadrilateral ABCD=53+19=72 square units..
____________________________
____________________________
Thank you...⭐️⭐️⭐️
___________________________
___________________________
The answer of u r question is....
Ans:
By joining B to D ,you will get two triangles ABD,BCD.
The area of triangle ABD
=1/2[-5(-5-5)+(-4)(5-7)+4(7+5)
=1/2(50+8+48)=106/2=53 square units....
Also,
The area of triangle BCD =1/2[-4(-6-5)-1(5+5)+4(-5+6)
=1/2[44-10+4]=19 square units...
Area of Triangle ABD + area of triangle BCD
so,
the are of quadrilateral ABCD=53+19=72 square units..
____________________________
____________________________
Thank you...⭐️⭐️⭐️
Answered by
3
Answer:
72
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