If a=-5 and d= 3 and sn=110 find nth term
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Given , a= -5
d= 3
Sn = 110
=> (n/2) {2a + (n-1)d} = 110
=> (n/2) { 2×(-5) + (n-1)3 } =110
=> (n/2) { (-10) + 3n - 3} = 110
=> n( 3n- 13) = 110×2
=> 3n^2 - 13n - 220 =0
=> 3n^2 - 33n +20n - 220 =0
=> 3n( n - 11) + 20(n -11) =0
=> (3n + 20)(n - 11) =0
So ,
3n-20 = 0
=> 3n = 20
=> n = 20/3
{not expectable}
or n-11 =0
=> n = 11
Therefore
N = 11
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