if (A)=5 and n(B)=7 then number of relations on A×B
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Answer:
a = 5
b=7
a*b =5*7=35
drishtikaushik2310:
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n(A×B)=?
n(A)=5 and n(B)=7
A×B = 5×7=35
n(A×B)= 35
Number of relation on A×B is 2^n = 2^35= 34359738368
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