Question

if a = 5, b = 3 ,c= 1,D =0 find the value of a square + 3 b square + 4c
square​

Answer 1

$a = 5 \\ b = 3 \\ c = 1 \\ d = 0$

To solve:

${a}^{2} + 3 {b}^{2} + 4c$

Putting values of a,b and c in the equation.

${5}^{2} + 3 \times {3}^{2} + 4 \times 1$

$= 25 + 3 \times 9 + 4$

$= 2 5 + 27 + 4$

$= 56$

Answer 2

Step-by-step explanation:

first number

1 5 square+3 × 3square+ 4× 1square

2 25+27+1

3 53 is answer