Math, asked by masterwarrior, 11 months ago

If a=5, b=6 and Angle A=45° then find Angle B

by properties of triangles​

Answers

Answered by srilakshmi23
0

formula: a/sinA=b/sinB

5/sin45°=6/sinB

5/(1/√2)=6/sinB

5√2=6/sinB

sinB=6/5√2

sinB=3√2/5

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