Question

If a = -5, b = -6 and c = 10.
Then find the value of :-

$\large{\bf{\frac{a³+b³+c³-3abc}{ab+bc+ca-a²-b²-c²} }}$
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[Note:- Kindly don't answer irrelevant answer and don't copy from other sites....and if possible then give short tricks to solve these type of questions.]​

Answer 1

Answer:

If a = -5, b = -6 and c = 10.

Then find the value of :-

$\large{\bf{\frac{a³+b³+c³-3abc}{ab+bc+ca-a²-b²-c²} }}$

[Note:- Kindly don't answer irrelevant answer and don't copy from other sites....and if possible then give short tricks to solve these type of questions.]

Step-by-step explanation:

Yes, whoever answers do this only.

Sorry I don't know the answer.

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Answer 2

If a = -5, b = -6 and c = 10.

Then find the value of :-

$\huge\color{darkblue}{\bf{\frac{a³+b³+c³-3abc}{ab+bc+ca-a²-b²-c²} }}$

ab+bc+ca−a²−b²−c²

a³+b³+c³−3abc

Hope it helped you ✌