Question

if a =-5 b = -6 c =10 find the value of a^3+b^3+c^3-3abc/ab+bc+ca-a^2-b^2-c^2
most great answer which is understandable gets brainliest and 15 pts pls answer fast!!

Answer 1

Given

a= -5

b= -6

c= 10

As per the problem the given equation is

a^3+b^3+c^3-3abc/ab+bc+ca-a^2-b^2-c^2

substitute the given values

-5^3+(-6^3)+10^3-(3×-5×-6×-10)/(-5×-6)+(-6×10)+(10×-5)-(-5^2)-(-6^2)-(10^2) =========== 1st step

-125+(-216)+1000-(-900)/30+(-60)+(-50)-(25)-(36)-(100)========== 2nd step

-125-216+1000+900/30-60-50-25-36-100======= 3rd step

-341+1900/30-271 ========= 4th step

1559/-241 ======== 5th step

-6.4688 is the resultant answer