if a=5 d=2 find asthmatic progression
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a=5 d=2
1st term = 5
2nd term = a+d
=5+2=7//
3nd term = a + 2d
= 5+2(2) = 5+4 = 9//
4th term = a + 3d
=5+ 3(2)=5+6=11//
5th term = a + 4d
= 5 + 4(2)=5+8=13//
6th term = a +5d
= 5 + 5(2) = 5+10=15//
so the arithmetic progression = 5 , 7 , 9 , 11 , 13 , 15
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