Question

If a= 5 , d= 3 find 11th and 17 term for class 7 with solution

Answer 1

Answer:

we know that the nth term of the arithmetic progression is given by a+(n−1)d

Given that the 17 th term is 5 more than twice the 8 th term.

Therefore, 5+17 th term=2(8 th term)

⟹a+(17−1)d=2(a+(8−1)d)+5

⟹a+16d−5=2a+14d

⟹a−2d=−5 -------(1)Given that the 11 th term is 43

Therefore, a+(11−1)d=43

⟹a+10d=43 ------(2)

subtracting (1) from (2) we get

(a+10d)−(a−2d)=43−(−5)

⟹12d=48

⟹d=4

⟹a=3

Therefore, the n th term is 3+(n−1)4=4n−1

hope it helps you☺

Answer 2

this is the answer solve it