If a(5+q²)+2bq+c=0 and a(5+r²)+2bq+c =0 where a≠0 then q+r=
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Consider the quadratic equation a(p+x)2+2bpx+c=0 this has two roots and given that q,r satisfy the equation implies q,r are the roots of this equation. Rewriting the equation as ax2+2px(a+b)+(c+ap2)=0 the product of the roots qr is given by constant term divided by coefficient of x2 .
∴qr=c+ap2a
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if p and q be the roots of the given quadratic equation then, a(5+r^2) + 2br + c = 0 and a(5+q^2) + 2bq + c = 0
so, consider the equation
a(5+x^2) + 2bx + c = 0
whose roots are q and r
then we write that as
ax^2 + 2bx + a + c = 0
where q + r = -2b/a
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