Question

If A[57] B[4, 5] c[-1, -6] and D [4, 5] the vertices & a quadrilateral thin find the quadrilateral ABCD​

Answer 1

Let the vertices of the quadrilateral be A(−5,7),B(−4,−5),C(−1,−6),D(4,5).

Joining AC there are two triangles ABC,ADC

Therefore area of quadrilateral ABCD=Area of ΔABC+Area of ΔADC

Area of ΔABC=21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]

Here x1=−5,y1=7,x2=−4,y2=−5,x3=−1,y3=−6

Area of ΔABC=21[−5(−5+6)−4(−6−7)−1(7+5)]=21(35) square units.

Area of ΔADC=21[x1(y2

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