Math, asked by kumarvishwjeet1805, 3 months ago

if A = 5cm , b=12cm ,c = 13cm what is the area of triangles abc​

Answers

Answered by anindyaadhikari13
3

Required Answer:-

Given:

  • Sides of a triangle measures 5cm, 12cm and 13cm.

To Find:

  • The area of the triangle.

Solution:

We have,

  1. a = 5 cm.
  2. b = 12 cm.
  3. c = 13 cm.

Area of a triangle is calculated by heron's formula,

 \sf \implies A =  \sqrt{s(s - a)(s - b)(s - c)}

Where,

  1. s = semi perimeter of the triangle, s = (a + b + c)/2
  2. a, b and c are the sides of the triangle.

Calculate the value of s.

 \sf \implies s =  \dfrac{a + b + c}{2}

 \sf \implies s =  \dfrac{5 + 12 + 13}{2}

 \sf \implies s =  \dfrac{30}{2}

 \sf \implies s = 15

Hence, the area of the triangle will be,

 \sf \implies A =  \sqrt{15(15 - 5)(15 - 12)(15 - 13)}

 \sf \implies A =  \sqrt{15 \times 10 \times 3 \times 2}

 \sf \implies A =  \sqrt{3 \times 5 \times 5 \times 2\times 3 \times 2}

 \sf \implies A =  \sqrt{ {(3 \times 5 \times 2)}^{2} }

 \sf \implies A =  \sqrt{ {30}^{2} }

 \sf \implies A =  30cm^{2}

Hence, the area of the triangle is 30 cm².

Answer:

  • Area - 30cm²
Answered by anshu24497
4

 \large{ \textsf{ \textbf{ \color{royalblue}{Given \: :}}}}

  • Sides of a triangle measures 5cm, 12cm and 13cm.

 \large{ \textsf{ \textbf{ \color{royalblue}{To \:  Find : }}}}

  • The area of the triangle.

 \large{ \textsf{ \textbf{ \purple{Solution \: :}}}}

We have,

  • a = 5 cm
  • b = 12 cm
  • c = 13 cm

Area of a triangle is calculated by heron's formula,

\sf{ \green{ \implies A = \sqrt{s(s - a)(s - b)(s - c)}}}

Where,

  • s = semi perimeter of the triangle, s = (a + b + c)/2
  • a, b and c are the sides of the triangle.

Calculate the value of s.

\sf \implies s = \dfrac{a + b + c}{2}

\sf \implies s = \dfrac{5 + 12 + 13}{2}

\sf \implies s = \dfrac{30}{2}

\sf \implies {\red{s = 15}}

Hence, the area of the triangle will be,

\sf \implies A = \sqrt{15(15 - 5)(15 - 12)(15 - 13)}

\sf \implies A = \sqrt{15 \times 10 \times 3 \times 2}

\sf \implies A = \sqrt{3 \times 5 \times 5 \times 2\times 3 \times 2}

\sf \implies A = \sqrt{ {(3 \times 5 \times 2)}^{2}}

\sf \implies A = \sqrt{ {30}^{2} }

\sf \implies{\red{ A = 30cm^{2}}}

Hence, the area of the triangle is 30 cm².

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