Question

If A= 5i-2j+3k and B= 2i+j+2k, component of B along A is:

(a) √14 / 38
(b) 28 /√38
(c) √28 / 38
(d) 14/√38

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Answer 1

Answer:

Answer is option D

Explanation:

A.B vector =ABcostheta

(5i-2j+3k)(2i+j+2k)/(underoot 5^2+2^2+3^2)=component of b along a.

10-2+6/underoot38= component of b along a.

14/ square root 38= component of b along a.

Answer 2

Explanation:

Option D is correct

this is vector question