Physics, asked by saicharanchinna15, 9 months ago

If A+=5i^-2j^+3k^ and B~=2i^+j^+2k^,
component of B→ along A™ is
(A) 1438
(B) 2838
(C) 2838
(D)
1438​

Answers

Answered by max20
1

Explanation:

a.b=|a||b|cos they

component of b along a= mod b cos theta

= a.b/|a|

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