If A(6, –1), B(1, 3) and C(k, 8) are three points such that AB= BC, find the value of k.
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As, AB=BC
Using Distance Formula,
√25+4=√25+k sq. +1-2k
29=26+2k+k sq. =>K sq. +2k-3=0
=>K sq.+3k-k-3=0
=>k(k+3)-1(k+3)=0
=>(k+3)(k-1)
=>k=-3ork=1.
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