Question

If A (6,-1) , B (1,3) , c (k,8) are three points such that AB = AC , find the value of k. Plzzzz tell as soon as possible....!!!!!

Answer 1

use here distance formula
AB=AC
root{(6-1)^2+(-1-3)^2}=root{(6-k)^2+(-1-8)^2}

squaring both side
(5)^2+(-4)^2=(6-k)^2+(-9)^2
25+16=(6-k)^2+81
41-81=(6-k)^2
-40=(6-k)^2
we know square is always positive
so this equation is not give value of k