if A(6,1), B(8,2) and C(9,4) are three vertices of a parallelogamABCD.Find the fourth vertex
IfE is the mid-pont of Dc, then find the area ofA ADe.
Answers
Answered by
1
Answer:
Step-by-step explanation:
Attachments:
Answered by
4
Let (x, y) be the coordinates of D and (x',y') be thee coordinates of E. since, the diagonals of a parallelogram bisect each other at the same point, therefore:
(x+8)/2 = (6+9)/2 x = 7
(y+2)/2 = (1+4)/2 y=3
Thus, the coordinates of D are (7,3).
E is the midpoint of DC
therefore x' = (7+9)/2 x'=8
y' = (3+4)/2
y'=7/2
Thus, the coordinates of E are (8,7/2)
Let A (x1,y1) = A (6,1),
E(x2,y2) = E(8,7/2) and D (x3,y3) = D(7,3)
Now Area (ΔABC) = 1/2[x1(y2 - y3)+x2(y3 - y1) + x3(y1 - y2)]
=1/2[6(7/2 - 3) + 8(3 - 1) + 7(1 - 7/2)]
=1/2[3/2]
=3/4 sq. unit .
Similar questions