if A(6,1),B(8,2),C(9,4)and(7,3) are the vertices of quadrilateral ABCD show that quadrilateral ABCD is a parrlelogram
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Step-by-step explanation:
A(6,1)
B(8,2)
C(9,4)
D(7,3)
m(AB)=y2-y1/x2-x1
=2-1/8-6
=1/2
m(BC)=y2-y1/x2-x1
=4-2/9-8
=2
m(CD)=y2-y1/x2-x1
=3-4/7-9
=1/2
m(AD)=y2-y1/x2-x1
=3-1/7-6
=2
HENCE,ABCD is a parallelogram
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