if A(6,1),B(8,2)C(9,4)and D(7,3)are the vertices of squareABCD, then show that square ABCD is a parallelogram
Answers
Given : A(6,1),B(8,2)C(9,4)and D(7,3)are the vertices of Quadrilateral ABCD
To find : show that ABCD is a parallelogram
Soluion:
A(6,1),B(8,2)C(9,4)and D(7,3)
Slope of AB = (2 - 1)/(8 - 6) = 1/2
Slope of BC = (4 - 2)/(9-8) = 2
Slope of CD = (3 - 4)/(7-9) = 1/2
Slope of AD = (3 - 1)/(7 - 6) = 2
Slope of AB = Slope of CD
Slope of BC = Slope of AD
Opposite sides are parallel
Hence A(6,1),B(8,2)C(9,4)and D(7,3)are the vertices of parallelogram
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