Math, asked by jecy83, 11 months ago

If a=6+2√3 find the value of a-1/a​

Answers

Answered by tanyagoyal0110
1

Answer:

a = 6 + 2 \sqrt{3} \\  \frac{1}{a}  =  \frac{1}{6 + 2 \sqrt{3} }  \times   \frac{6 - 2 \sqrt{3} }{6 - 2 \sqrt{3} }  \\  =  \frac{6 - 2 \sqrt{3} }{(6) {}^{2}  - (2 \sqrt{3) {}^{2} } }  \\  =  \frac{6 - 2 \sqrt{3} }{36 - 12}  \\  =  \frac{6 - 2 \sqrt{3} }{24}  \\  = \frac{2(3 -  \sqrt{3} )}{24}  \\  =  \frac{3 -  \sqrt{3} }{12}

I hope it helps u...

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Answered by nilesh102
0

hi mate,

Answer: A = 6+2√3

1/a = 1/6+2√3

→ = 1/6+2√3 × 6-2√3/6-2√3

→ = (6-2√3)/(6+2√3)(6-2√3)

→ = (6-2√3)/(6²-(2√3)²)

→ = (6-2√3)/(36-4(3))

→ = (6-2√3)/(36-12)

→ = (6-2√3)/24

★a-1/a

→ 6+2√3 - (6-2√3)/24

→ {24(6+2√3) - 6 + 2√3}/24

→ {144+48√3-6+2√3}/24

→ {138+50√3}/24

→ 138/24 + 50√3/24

→ 23/4 + 25√3/12

→ {69+25√3}/12

i hope it helps you.

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