Question

if a=6-√35,find the value of a²+1/a².

Answer 1

a^2 + 1/a^2
=(a+1/a)^2 -2.a.1/a
={(6-√35) + 1/(6-√35)^2 - 2
={(6-√35) + (6+√35)/(6-√35)(6+√35)}^2 - 2
={(6-√35) + (6+√35)/(36-35)}^2 - 2
={(6-√35)+(6+√35)}^2 -2
={12}^2 - 2
=144-2
=142

Hope you get it.

Answer 2

The solution is as follows