If a= 6 - √35,find the value of a²+1/a² please answer it properly
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0
Answer:
HERE IS UR ANSWER
Step-by-step explanation:
a=6-_/35
1/a=1/(6-_/35)=(6+_/35)(6^2-35)=6+_/35 (rationalised the denominator)
So, a^2+1/a^2=(6-_/35)^2(6+_/35)^2
=36+35-12_/35 +36+35+12_/35
=71+71=142...
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Answered by
0
Step-by-step explanation:
a^2+1/a
So, put the value of a
=(6-(√35))^2+1/(6-(√35))^2
=(36-35)+1/(36-35
=1+1/1
=2/1
=2
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