if a=6 and b=2 find the value of
1)a+6b/5a-3b ans is-3/4
2)2ab+7b-10/4ab-3a-2 ans is-1
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Solution:
It is given that, a=6 , b=2
Now ,
i) Value of (a+6b)/(5a-3b)
= [6+6×2]/[5×6-3×2]
= (6+12)/(30-6)
= 18/24
= (3×2×3)/(3×2×4)
After cancellation we get
= 3/4
ii) Value of
(2ab+7b-10)/(4ab-3a-2)
= (2×6×2+7×2-10)/(4×6×2-3×6-2)
= (24+14-10)/(48-18-2)
= 28/28
= 1
••••
sujata56:
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