Question

If a=6, b=-3 and c=1, then find the value of 1/(b-c)(c-a)+1/(c-a)(a-b)+1/(a-b)(b-c)

Answer 1

Answer:

b minus c × c minus a=20

c minus a× a minus b = minus45

a mins b× b minus c=minus 36

Step-by-step explanation:

then

1÷20_1÷-45_1÷_36

0.05_ 0.022222 _0.27778=0

answer is 0