if a=6,b=3, and c=7, the value of 2a2+3b2-7c2 is ____________
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Answer:
a = 6
b = 3
c = 7
then 2a2 + 3b 2 - 7c2 =
(2 x 6 x 2 )+ (3 x 3 x 2 )-( 7 x 7 x 2 )
24 + 18 - 98
42 - 98
-56
Hope it helps !
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