Math, asked by mk127907, 7 months ago

If a^6-b^6=8(a^4+b^4+a^2b^2than. a^2-b^2=?

Answers

Answered by nikitaroylairik
0

Answer:

a²-b² = 8

Step-by-step explanation:

a⁶ - b⁶

= (a²)³ - (a²)³

= (a²- b²) ( a⁴+b⁴ + a²b²) { since yk a³- b³ = (a-b)

× (a²+b²+ab) }

Hence , it is given in the question that

a⁶-b⁶ = 8 ( a⁴+b⁴+a²b²)

Therefore , a²- b² = 8

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