if A=60 and B=30 prove that tan (A - B)=tan A-tan B/1+tan A.tan B
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Answer:
1/✓3
LHS=RHS
Step-by-step explanation:
Hello,
A=60° B=30°
LHS=tan(A-B)=tan(60°-30°)
=tan(30°) which is equal to 1/√3
now,
RHS=tanA-tanB/1+tanAtanB
=tan60°-tan30°/1+tan60°tan30°
tan60°=√3 tan30°=1/√3
=√3-1/√3/1+√3·1/√3
in numerator taking LCM
=(√3·√3-1)/√3/1+1 √3×1/√3=1
=(3-1)/√3/2
=2/√3/2
2/√3×1/2
=1/√3
LHS=RHS
hence verified
hope this helps you buddy
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