Math, asked by sanjay6359, 4 hours ago

If A = 60 B = 30 Prove that Sin(A+B) = Sin A Cos B + Cos A Sin B​

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Answered by gayenbanasree
0

Answer:

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Answered by Anonymous
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sin(A + B) = sinA cosB + cosA sinB

Proof of statement:

Given, A = 60° and B = 30°

∴ L. H. S. = sin(A + B)

= sin(30° + 60°)

= sin90°

= 1

∴ R. H. S. = sinA cosB + cosA sinB

= sin60° cos30° + cos60° sin30°

= (√3)/2 * (√3)/2 + 1/2 * 1/2

= 3/4 + 1/4

= (3 + 1)/4

= 4/4

= 1

L. H. S. = R. H. S.

Thus proved.

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