If A = 60 B = 30 Prove that Sin(A+B) = Sin A Cos B + Cos A Sin B
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sin(A + B) = sinA cosB + cosA sinB
Proof of statement:
Given, A = 60° and B = 30°
∴ L. H. S. = sin(A + B)
= sin(30° + 60°)
= sin90°
= 1
∴ R. H. S. = sinA cosB + cosA sinB
= sin60° cos30° + cos60° sin30°
= (√3)/2 * (√3)/2 + 1/2 * 1/2
= 3/4 + 1/4
= (3 + 1)/4
= 4/4
= 1
∴ L. H. S. = R. H. S.
Thus proved.
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