Question

If A=60 degree , then 3sinA³-4sinA
plz answers chapava​

Answer 1

Here's ur answer.

Hope it helps u.

Answer 2

$3 \sin( {60}^{0} ) - 4 \sin( {60}^{0} )$

$3 \times \frac{ \sqrt{3} }{2} - 4 \times \frac{ \sqrt{3} }{2}$

$\frac{6 \sqrt{3} }{2} - \frac{8 \sqrt{3} }{2}$

$3 \sqrt{3 } - 4 \sqrt{3}$

$\sqrt{3} (3 - 4)$

$\sqrt{3} ( - 1)$

$\frac{ + }{ } \sqrt{3}$