If A=60 degree verify that sin2A=2tanA/1+tan^2A
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A = 60
then
LHS
sin 120
= sin (90+30)
= cos 30
= √3/2
RHS
= (2tan60) / (1 + tan²60)
= (2√3) / 1 +3
= 2√3 / 4
=√3/2
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then
LHS
sin 120
= sin (90+30)
= cos 30
= √3/2
RHS
= (2tan60) / (1 + tan²60)
= (2√3) / 1 +3
= 2√3 / 4
=√3/2
am I right?
then please follow me
and
mark me BRAINLIST !!!
Thank you
Rushikeshswami:
hi
Answered by
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Step-by-step explanation:
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