Question

If a 60 ml of water contains 12% of chlorine, how much water must be added in order to create a 8% chlorine solution?​

Answer 1

Given :

• total quantity of water is 12%
• contain 12% of chlorine

ㅤ

To find :

• how much water must be added in order to create a 8% chlorine solution

ㅤ

Solution :

Let x ml of chlorine be present in water.

Then,

= $\frac{12}{100}$

= $\frac{x}{60}$

→ X = 7.2 ml

ㅤ

Therefore, 7.2 ml is present in 60 ml of water.

ㅤ

In order for this 7.2 ml to constitute 8% of the solution, we need to add extra water.

Let this be y ml.

ㅤ

Then,

→ $\frac{8}{100}$ = $\frac{7.2}{y}$

→ y = 90 ml.

So in order to get a 8% chlorine solution, we need to add 90 - 60 = 30 ml of water.

Answer 2

Answer:

here is your answer ....