Question

If a 60 ml of water contains 12% of chlorine, how much water must be added in order to create a 8% chlorine solution?

Answer 1

Let x ml of chlorine be present in water.

Then, 12/100 = x/60 → x = 7.2 ml

∴, 7.2 ml is present in 60 ml of water.

In order for this 7.2 ml to constitute 8% of the solution, we need to add extra water. Let this be y ml.

Then, 8/100 = 7.2/y → y = 90 ml.

So in order to get a 8% chlorine solution, we need to add 90-60 = 30 ml of water.       ans

hope this will help you

Answer 2

Answer:

30 ml

Step-by-step explanation:

(8/100)*x=(12/100)*60

8x=12*60

x=(12*60)/8

x=90 ml

Therefor, water need to add in order to create a 8% chlorine solution= (90-60) ml  = 30 ml