If A=60; show that
Sin 3A = 4 sin A sin (60 - A) sin (60+A)
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Answer:
sin3A=4sinA sin(60-A) sin(60+A)
sin3(60)=4sin60 sin(60-60) sin(60+60)
sin180= 2×root3 ×0×sin120
sin180=0
thanks
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