Question

If A = 60° and B = 30°,cos (A-B) = cos A cos B + sin A sin B​

Answer 1

Given: A=60° and B =30° Now, LHS = Cos (A+B) ⇒ Cos (60° + 30°) ⇒ Cos (90°) ⇒ 0 [∵ cos 90° = 0] Now, RHS = Cos A Cos B – Sin A Sin B ⇒ cos(60°) cos(30°) – sin(60°) sin (30°) ⇒ 0 ∴ LHS = RHS Hence

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Answer 2

If A = 60° and B = 30°,cos (A-B) = cos A cos B + sin A sin B