Math, asked by wwwkritikagaur, 1 year ago

If a = 60° and b = 30°
(i) sin (A-B)
___________ = Cot B - cot A
Sin A sin B

Answers

Answered by princepriyanshu
0
A = 60 and B = 30.

Sin (A+B)/CosA.CosB

LHS :

Sin(A+B)/CosA.CosB = (SinA.CosB + CosA.SinB)/CosA.CosB

= (SinA.CosB/CosA.CosB) + (CosA.sinB/CosA.CosB)

Cancelling common terms from numerators and denominators

= SinA/CosA + SinB/CosB = TanA + TanB .



A = 60 and B = 30.

Sin (A+B)/CosA.CosB

LHS :

Sin(A+B)/CosA.CosB = (SinA.CosB + CosA.SinB)/CosA.CosB

= (SinA.CosB/CosA.CosB) + (CosA.sinB/CosA.CosB)

Cancelling common terms from numerators and denominators

= SinA/CosA + SinB/CosB = TanA + TanB .

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