Question

if A=60° and B=30° prove that tan (A -B)=tan A -tanB /1+ tan A ×tan B​

Answer 1

Answer:

i will say u how to do

just substitute the values on both sides

taking LHS and RHS

u get equal to 1/root3

so hence proved

HOPE THIS ANSWERS will help u

Answer 2

To prove:  tan (A-B) = tan A - tan B / 1 + tan A x tan B,      A=60° and B=30°

LHS:

tan (60 - 30) = tan 30° = 1/$\sqrt{3}$

RHS:

tan 60° - tan 30° / 1 + tan 60° x tan 30° = ($\sqrt{3}$ - 1/$\sqrt{3}$) / (1 + $\sqrt{3}$ x 1/$\sqrt{3}$)

= {(3 - 1) /$\sqrt{3}$ } / (1 + 1) = 2 / 2$\sqrt{3}$ = 1/$\sqrt{3}$ = LHS

Hence proved

Hope I helped