If A
= 60° and B = 30°, then pro
that tan (A-B) = tanA - tanbove
1+tanAtanB
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Answer:
First, substitute the values of A and B:
tan(60°- 30°) = [tan(60°) - tan(30°)]/1 + tan30tan60
tan30 = [√3 - 1/√3]/[1 + √3•1/√3]
1/√3 = [(3-1)/√3]/2
1/√3 = 2/2√3
1/√3 = 1/√3
L.H.S = R.H.S
hence proved.
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