Question

If A=60°, B=30° then sinB÷1-cosB+sinB÷1+cosB=?​

Answer 1

Answer:

Explanation:

Given,

A = 60° , B = 30°

Now,

sin(A - B) = sinA cos B - cos A sin B.

Substituting A = 60 , B = 30°

sin(60 - 30 ) = sin60cos30- cos 60sin 30

We know, Trigonometry ratios of particular angles : sin90 = 1 , sin30 = 1/2 , sin60 = √3/2 , cos30 = √3/2 , cos60 = 1/2

sin30 = √3/2 ( √3/2 ) - 1/2 ( 1/2 )

1/2 = 3/4 - 1/4

1 /2= 2/4

1/2 = 1/2

Both Sides of the equation are equal.

Hence, We proved and verified that sin(A - B) = sinA cos B - cos A sin B. holds good for A = 60, B = 30°